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4.60 In a town, 45% of all households have a pet, 35% have children, and 40% of all households with children have a pet. Using

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4.60 In a town, 45% of all households have a pet, 35% have children, and 40% of all households with children have a pet. Using these definitions: P = event household has a pet C = event household has children a. Complete the following contingency table. P P' Total C C' b. From part (a) or otherwise, answer the following: i. What is the probability that a randomly selected household has neither pets nor children? ii. What proportion of households with children do not have a pet? iii. Find and interpret P(C | P)

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