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5. [0/1 Points] PREVIOUS ANSWERS U.S. Population YEAR POPULATION 1930 122,800,000 1940 131,700,000 1950 150,700,000 1960 179,300,000 It is estimated that the limiting population that

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5. [0/1 Points] PREVIOUS ANSWERS U.S. Population YEAR POPULATION 1930 122,800,000 1940 131,700,000 1950 150,700,000 1960 179,300,000 It is estimated that the limiting population that the United States can support is 500,000,000 people. Predict the population for the year 2000 using the logistic growth model on the basis of the data in the years 1930 and 1940. In other words: 0 Let P = P (t) be the population. where t is the number of years after 1930, - Assume P (t) is of the form given by the logistic equation. Determine what the value of L must be in this case. 0 Find the exact values of P (0) and P (10) from the US. Population mble given above. Use these two data points to nd the values of b and k in the formula for P (t). Note: Answer to the nearest 1 million people, and do not use commas in your answer. _ Viewing Saved Work Revert to Last Response Submit Answer 6. [-I1 Points] A radioactive substance has a decay rate of 3.2% per year. What is its half life? Give your answer correct to 2 decimal places. years 7. [-I1 Points] The radioactive element carbon-14 has a half-life of 5750 years. The percentage of carbon-14 present in the remains of plants and animals can be used to determine age. How old is a skeleton that has lost 56% of its carbon-14? Note: Do not round any numbers during your calculation. years old 8. [-I1 Points] By Newton's Law of Cooling, the rate at which an object cools is directly proportional to the difference in temperature between the object and the surrounding medium. If a certain object cools from 115 to 90 in half an hour when surrounded by air at 70, find its temperature at the end of another half hour. 0 9. [-I1 Points] Find the present value of $20000 due 11 years later at 6.7%, compounded continuously. $ 10. [-/1 Points] which function satisfies the equation below? (c is an arbitrary constant.) % = (0.7)R R = c(o.35)R2 R = c(0.35)t2 R = ce('7>t R = z:(0.7)t R=z:et

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