5 (3 points) Let f (T) = Then according to the definition of derivative T -5 f'(x) = lim h-+0 (Your answer above and the next few answers below will involve the variables / and I.) The expression inside the limit simplifies to a simple fraction with: Numerator = Denominator = NOTE: Both of the previous two parts must be correct in order to receive partial credit. We can cancel the factor appearing in the denominator against a similar factor appearing in the numerator leaving a simpler fraction with: Numerator = Denominator = NOTE: All three of the previous parts must be correct to receive partial credit. Taking the limit of this fractional expression as h - 0 gives us f'(x) =