$5\mathrm{.}40$ Water is pumped from a tank, point $(1),$ to the top of a water

plant aerator, point $(2),$ as shown in Fig. P$5\mathrm{.}40$ at a rate of $3\mathrm{.}0f\frac{t^3}{s}.$

$($a$)$ Determine the power that the pump adds to the water if the head

loss from $(1)$ to $(2)$ where $V_2=0$ is $4ft.($b$)$ Determine the head

loss from $(2)$ to the bottom of the aerator column, point $(3),$ if the

average velocity at $(3)$ is $V_3=2f\frac{t}{s}.$

Figure P$5\mathrm{.}40$

Please write the solution to part a in joules and part b in ft$.$ Also please solve this problem using energy equation, finding $w_{\text{s}\text{h}\text{a}\text{f}\text{t}}=\frac{W_{\text{s}\text{h}\text{a}\text{f}\text{t}}}{\text{m}\text{a}\text{s}\text{s}\text{f}\text{l}\text{o}\text{w}\text{r}\text{a}\text{t}\text{e}}$ first. Thank you.