5. In figure on the right, a beam of monochromatic light hits passes through three mediums, crossing two interfaces as shown below. The indices of refraction or material 1 and 3 are n = 1.33 and n3 = 1. The index of refraction of material 2 is unknown. At the first interface, between materials 1 and 2, it hits point A at an angle of 50relative to the surface, partly reflects, and partly refracts at the angle 92=290. 72 2 = 1.33 50 B (a) Label the following angles in the figure and determine their values: 3 = 1 Air Angle of incidence 91= I Reflected angle 1'= Refracted angle 92= 29. (b) Plug in the values of m = 1.33, your value of 91, and 92 = 290 into Snell's law to find n2. Snell's law: nsin(91) = n2sin(92) At the second interface, between materials 2 and 3, it hits point B and both reflects at angle ' and refracts into the air at angle 93. (c) Label the following angles in the figure and determine the values of angles 92 and 92' only. Angle of incidence 2= Reflected angle 2 Refracted angle 3 = (d) What are the speeds of light in medium 1 and medium 2? (e) Extra Credit: Given the index of refraction you found in (b), use Snell's law to calculate the refracted angle 03.