5. The Company collected a sample of the salaries of its employees. There are 70 salary data points summarized in the frequency distribution below: Number of Employees 5,001 10,000 10,001- 15,000 15,001-20,000 20,001-25,000 25,001-30,000 (5,001+10,000)/2 = 7,500.5 (10,001+15,000)/ 2 = 12,500.5(15,001+20,000)/ 2 = 17,5005 (20,001+25,000)/ 2 = 22,500.5 (25,001+30,000)/ 2 = 27,5005 7500.5x8 = 60004.00 12500.5x12 =150006.00 17500.5)(20 =350010.00 22500.5x17 =382508.50 27500.5x13 =357506.50 Mean = 1300034/70=18571.93 a. Find the standard deviation. 39109183.67 square rooted to nd the standard deviation of 6267.72 b. Find the variance. Found by calculating the sum of the difference between each data point and mean then squaring it and then multiplying it by the frequency, Then divide the sum of all points by the number of data points to get variance which is 39209183.67