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5A.6 A survey with three strata is planned to estimate the percentage of families who have accounts in savings banks and the average amount invested

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5A.6 A survey with three strata is planned to estimate the percentage of families who have accounts in savings banks and the average amount invested per family. Advance estimates of the percentages Ph and the within-stratum Sh for the amount invested are as follows. Compute the smallest sample sizes n and the nh that satisfy the following requirements: (a) The percentage of families is to be estimated with s.e. =2 and the average amount invested with s.e. =$5. (b) The percentage of families is to be estimated with s.e. =1.5 and the average amount invested with s.e. =$5. Part (b) requires a compromise allocation, either by a computer program or the method in the second edition, p. 123 . The allocation nh=371,344,315, with n=1030 satisfies both tolerances. Show that the Booth-Sedransk method (section 5A.4 ) gives nh=0.431, 0.326,0.243. This allocation would require n=1073 to meet both tolerances. 5A.6 A survey with three strata is planned to estimate the percentage of families who have accounts in savings banks and the average amount invested per family. Advance estimates of the percentages Ph and the within-stratum Sh for the amount invested are as follows. Compute the smallest sample sizes n and the nh that satisfy the following requirements: (a) The percentage of families is to be estimated with s.e. =2 and the average amount invested with s.e. =$5. (b) The percentage of families is to be estimated with s.e. =1.5 and the average amount invested with s.e. =$5. Part (b) requires a compromise allocation, either by a computer program or the method in the second edition, p. 123 . The allocation nh=371,344,315, with n=1030 satisfies both tolerances. Show that the Booth-Sedransk method (section 5A.4 ) gives nh=0.431, 0.326,0.243. This allocation would require n=1073 to meet both tolerances

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