6. Question Details A 0.0210 kg bullet moving horizontally at 500 m/'s embeds itself into an initially stationary 0.500 kg block. (a) What is their velocity just after the collision? m/s (b) The bullet-embedded block slides 8.0 m on a horizontal surface with a 0.30 kinetic coefficient of friction. Now what is its velocity? m/s (c) The bullet-embedded block now strikes and sticks to a stationary 2.00 kg block. How far does this combination travel before stopping? m a) cons, of momentum : m. v. + mive = ( m, +me )v. b) enugy: KE; = KEg + Wfriction " 3 +MV= +MV' 2 + ANAX? when N= Mg ( ) momentum: MV, + mav = ( M + my )V stopped by friction: AKE = Weriction + mv? = UNAX