#6 Set up the iterated integral required to compute the value of JJs (x2 +y? + =?) dS ifS is the first octant portion of the cylinder x? + y = 4 bounded by the coordinate planes and the plane x + = = 2. Do not evaluate this integral. 2-1 2 ( 4 + = ) * The answer is 0 V (4 -x2))#11 F = S is the surface of the solid bounded by the graphs = =x- + y and = =4. .211 21I Ardrde + (cos?(0) - 3sin? (0) ) * r*drd0 The answer is JO 0