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600, Do0 = 1 ( 1000 kg ) V 2 V= 34:64 m/s 16. If there aren't any non-conservative forces acting on the car, then
600, Do0 = 1 ( 1000 kg ) V 2 V= 34:64 m/s 16. If there aren't any non-conservative forces acting on the car, then the gravitational potential and kinetic energies of the car may transferable ,but the total mechanical energy of the car will be the same 17. Suppose there was a non-conservative force of friction acting on the car. What would happen to the total mechanical energy of the car from the start of the track to the end of the track? the total mechanical energy wi'll m = 0.010 kg not be conserved. Vi = 0m -- STOP Model 3 (Application, 15 minutes) - Dart Pistol 0.050 m A spring-loaded, toy dart pistol is pointed straight up as shown in the figure here. k = 100 N/m A 0.010 kg dart is loaded into the pistol. As the dart is loaded, it compresses the spring inside the pistol by a distance of 0.050 m. The elastic constant of the spring is 100 N/m. Let the top of loaded dart be at the position y; = 0 m. N= (force ) = kg. m/s2 18. Before the gun is fired.. a. What is the initial (before the gun is fired) elastic potential energy of this system? Espring = = Kx = 2. 100 N/m . (0.05m) = = 0.125 kg my 2 b. What is the initial (before the gun is fired) gravitational potential energy of this system? 1 Fg= mgh = 6. 01 kg) ( 9.8 m/s' ) ( - o. 05m) = c. What is the initial (before the gun is fired) kinetic energy of this system? d. What is the total mechanical energy of this system before the gun is fired? 267 for foot Bel f
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