6.00mL of 4.00103MFe(NO3)3 (4.00 times 10 to the minus 3rd power MFe (NO3)3) is added to 8.00mL of 4.00103MKSCN(4.00 times 10 to the minus 3rd power MKSCN) along with 4.00mL of water. The concentration of [Fe(SCN)2+] was found to be 3.00104M(3.00 times 10 to the minus 4 th power M) at equilibrium. How many moles of Fe3+ are present in the solution at equilibrium? Express your answer as a decimal number (no exponents). Your Answer: Answer units