62 6+2) This is a non-ideal solution of neutral components, there tore near the dilution linut, the solvent will follow Raoult = 32 3 Finally the * 1907: Fluid Mechanics ! low and the solute will follows Henry's law. (a) Plot Ptot as a 'ood function of ore) B. Benzene, T: tomene. Also, plot (P3leq , Prdeg for the partial raporr pressures using Dalton's lawi (P; Jeg = P tot 8; 19), xy molar fraction in gas phese, prot 1 = 2.98 atm (pure B) . pure I 1:1,34 get the slope: ky (3) . Make the plot in Excel. I o AX ll) 1 1 X(e) = 16.262 ( point of interst, B: solute To Solvent) (b) We apply the convention I to the solvent (7) and the convention I to the solute (B): PB YB, I (51.2.1) (PB) real (B) (PB) Henry * (pt) real r (51.2.1) (P) Rasult betxe) PB Get po = Peat ? (?), by = Protx (1) by interpolation for pe 1= 0.262 in the table given. For K (B), plot 8 X (2) and estimate the slope at low values (dilution). B re b 1 essures. Titoluene. (St. : (51.3) T ab, I = B, IX 8 xe) Finally the activities are stand 97, I = 77,1 x) (51.3.1) 4,5 (c) for the AG mix, it's easier to compute it per total number of moles for the data given: My = x + Tha, - MB MB = I xle) RT tha; AG mix RT { x lencar, I + x) en as, I}