Answered step by step
Verified Expert Solution
Question
1 Approved Answer
6.785 Data Tables for Experiment 39C Data: Table 3: Data from Experiment 39C Mass of Green Compound for Al and A2 0-100g Mass of Green
6.785 Data Tables for Experiment 39C Data: Table 3: Data from Experiment 39C Mass of Green Compound for Al and A2 0-100g Mass of Green Compound for B1 and B2 0.701 g Absorbance of Al Solution 6.462 Absorbance of A2 Solution 10 - SIS Absorbance of BI Solution 0.$166 Absorbance of B2 Solution Molarity of [Fe(bipy);]** in Al 4.184M Molarity of [Fe(bipy);]*" in A2 4 SUM Molarity of [Fe(bipy);] in B1 6.759M Molarity of [Fe(bipy)]'' in B2 6533M Molarity of Fe in original A from Al M Molarity of Fe in original A from A2 M Molarity of Fe in original B from B1 M Molarity of Fe in original B from B2 M Moles of Fe(III)/100 g compound for Al moles Moles of Fe(III)/100 g compound for A2 moles Moles of Fe(III)/100 g compound for B1 moles Moles of Fe(III)/100 g compound for B2 moles Average Moles of Fe(III)/100 g compound moles Fe(III) /100 g compound Ratio of (C204) * to Fe(III) in Moles V=0.4375X -0.1133 Ai - (0.46236.1 375)x-0.1133 = 4.184 Az -(0.515.0.1375) -6.1133=4.560 B = 10.816 0.1375)x 0.1133 = 6.759 B2=(0.78560.1373)x0.11336.533 +
Step by Step Solution
There are 3 Steps involved in it
Step: 1
Get Instant Access to Expert-Tailored Solutions
See step-by-step solutions with expert insights and AI powered tools for academic success
Step: 2
Step: 3
Ace Your Homework with AI
Get the answers you need in no time with our AI-driven, step-by-step assistance
Get Started