$7\mathrm{.}5gKN{O}_3$ dissociated in $49\mathrm{.}0g$ of water in

a coffee cup calorimeter. The thermometer

reading changed from $20\mathrm{.}4C$ to

$9\mathrm{.}7C.$ What is the heat of the reaction?

$KN{O}_3{K}^{+}+N{O}_3^{-}$

$c_{soln}=4\mathrm{.}18\frac{J}{g}C,C_{\text{c}\text{a}\text{l}}=6\mathrm{.}5\frac{J}{}C$

$q_{rn}=,J$

Hint: Make sure to account for all parts of the

solution and calorimeter.

Enter either a $+$ or $-$ sign AND the magnitude.