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7. Discharging cycle Vc(t) = 3.63 V @ t-tao_ Vc(t) /Vmax = 0.3637 Comment: the drop = 1 - 0.3637 = 0.6363 We know after
7. Discharging cycle Vc(t) = 3.63 V @ t-tao_ Vc(t) /Vmax = 0.3637 Comment: the drop = 1 - 0.3637 = 0.6363 We know after one time constant, the change is 63%, from 100% down to 36.37%
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