. 71' 4. (2 pts} (3! Find 11113|:Jc2 cos [J] . Note that we can't use direct substitution! x) x (Hint: 0n [-1,1], what are the upper and lower bounds on cos[] ?) x it Scos S x - 71' Place answer here: 11m|:x2 cos [J] = :)U x (b) Sketch a rough graph of the functions y = x2 , y = x2 , and y = x2 cos[] on the interval at [-1,1]. You may use a graphing calculator to help with the third graph.