Question
7.13LAB: Leap year - methods A year in the modern Gregorian Calendar consists of 365 days. In reality, the earth takes longer to rotate around
7.13LAB: Leap year - methods
A year in the modern Gregorian Calendar consists of 365 days. In reality, the earth takes longer to rotate around the sun. To account for the difference in time, every 4 years, a leap year takes place. A leap year is when a year has 366 days: An extra day, February 29th. The requirements for a given year to be a leap year are:
1) The year must be divisible by 4
2) If the year is a century year (1700, 1800, etc.), the year must be evenly divisible by 400
Some example leap years are 1600, 1712, and 2016.
Write program that takes in a year and determines whether that year is a leap year.
Ex: If the input is 1712, the output is:
1712 is a leap year.
Ex: If the input is 1913, the output is:
1913 is not a leap year.
Your program must define and call the following method. The method should return true if the input year is a leap year and false otherwise.
public static boolean IsLeapYear(int userYear)
Note: This is a lab from a previous chapter that now requires the use of a method.
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