7238 .III '3' E} Find the mean, standard deviation, and the median of this sample (your answers must have two decimal places): 10, 12, 12, 15, 20, 27, 30, 31, 31, 31. (8 pts) The mean is , the st. deviation is , the median is Part II (Chapter 4). Answer the questions below by using given X-Values as your predictor column and given y-values as your response data. Construct the tted line plot (I will check it in your Minitab output window). The least squares regression line for this data is . The coefcient . . 2 . of determmation, R , 1s Write a short sentence explaining What the coefcient of determination tells us in this problem: (10 pts) \f7239 .II '3' C} Problem 1. Construct a condence interval of the population proportion at the given level of condence: X = 80, n = 200, 98% condence. When using Minitab, remember to choose the Summarized Data option and select \"Normal Approximation\". Your answer must be rounded to four decimal places. Please, write the answer here: (10 points) Problem 2. The given sample is 100, 110, 110, 112,115, 116, 116,116, 120, 121,122, 124, 124, 125. Construct two condence intervals for the mean of the population from which this sample was taken and write the answers below. They must be rounded to two decimal places. (12 points) The interval constructed with 90% condence level is The interval constructed with 95% condence level is Write a sentence about how the change in condence level affects the Width of the 1 7239 .II '3' C} Problem 2. The given sample is 100, 110, 110,112,115,116,116,116,120,121,122, 124, 124, 125. Construct two condence intervals for the mean of the population from which this sample was taken and write the answers below. They must be rounded to two decimal places. (12 points) The interval constructed with 90% condence level is The interval constructed with 95% condence level is A Q. Write a sentence about how the change in condence level affects the width of the interval: Problem 3. Use the same data as in problem 2 to construct a 95% condence interval for the variance. When going through Minitab menu, make sure to use Chi Square result, not the Bonnet one, and assume normal distribution. The values of the endpoints must be rounded to two decimal places. (12 points) 7239 .III '3' C} Problem 3. Use the same data as in problem 2 to construct a 95% condence interval for the variance. When going through Minitab menu, make sure to use Chi Square result, not the Bonnet one, and assume normal distribution. The values of the endpoints must be rounded to two decimal places. (12 points) Write the answer here: Part IV (Chapter 10). Problem 1. Test the hypothesis by using thee- p-values method. H0: p = 0.25versu3H1: p 02 at the (X = 0.05 level ofsignifican 7239 .III '3' C} Assume that the populations are normally distributed and test the given hypothesis: 01 > 02 at the OL = 0.05 level ofsignifican (10 points) Sample 1 Sample 2 n 23 13 s 7.5 5.1 The p-value for this test is Conclusion: we the null hypothesis (write in \"reject\" or \"fail to reject\"). There is evidence (write in \"sufcient\" or \"insufcient\") to support the original claim. A \\'L Part VI. Chapter 13. One measure of the value of a stock is its price to earnings ratio (or P/E ratio). It is the ration of the price of the stock per share to the earnings per share. A stock analyst wants to know-if-dqe-PE-mee-for three 7239 .III '3' C) One measure of the value of a stock is its price to earnings ratio (or P/E ratio). It is the ration of the price of the stock per share to the earnings per share. A stock analyst wants to know if the P/E ratios for three industry categories differ signicantly. The data in the table below represents simple random samples of companies from three categories: nancial, food, and leisure goods. Financial Food 8.83 19.75 12.75 17.87 13.48 15.18 14.42 22.84 10.06 15.60 (Source: Statistics: Informed Decisions Using Data, 6th Edition, Michael Sullivan III). Test the null hypothesis that the mean P/E ratio is the same for each category. Use 0.05 level of signicance. Assume that the A requirements for a one-way ANOVA are Q satised. Use ulfor the mean of the data in nancial category, \"2 for the mean of the data in the food category, and Hg for the mean of the data in the leisure goods Arm-ARA\7:40 II" a\" [3' Part VI. Chapter 13. One measure of the value of a stock is its price to earnings ratio (or P/E ratio). It is the ration of the price of the stock per share to the earnings per share. A stock analyst wants to know if the P/E ratios for three industry categories differ signicantly. The data in the table below represents simple random samples of companies from three categories: nancial, food, and leisure goods. Food Leisure Goods 19.75 14.10 17.87 10.12 15.18 22.84 15.60 (Source: Statistics: Informed Decisions Using Data, 6th Edition, Michael Sullivan 111). Test the null hypothesis that the mean P/E ratio is the same for each category. Use 0.05 level of signicance. Assume that the requirements for a one-way ANOVA are satised. Use ulfor the mean of the data in nancial category, p12 for the mean of the data in the food category, and 113 for the 0.1 7:40 II" a\" [3' Test the null hypothesis that the mean P/E ratio is the same for each category. Use 0.05 level of signicance. Assume that the requirements for a one-way ANOVA are satised. Use ulfor the mean of the data in nancial category, [12 for the mean of the data in the food category, and H3 for the mean of the data in the leisure goods category. (14 points) The null hypothesis is: The alternative hypothesis is: p-Value obtained after running the ANOVA test is p-Value is than alpha. We the null hypothesis (write in \"reject\" or \"fail to reject\"). It means that A Q (write one of two possible conclusions: all means are the same OR at least one mean is JZL'L'______A.\\ 7:40 II" a\" [3' 1'6] CC . means a (write one of two possible conclusions: all means are the same OR at least one mean is different). If at least one mean is different, run the Tukey test to specify which mean is different. Write down this mean below and explain your conclusion (what result of the Tukey test points at the different mean). Note that there is an example of a similar case posted in Canvas. Please, insert your answer to the question in the paragraph above here: )