8. (15 points) This problem is taken from 12-23 of the course textbook, Adams and Lee. (Radiation efficiency of an antenna) In practice, the radiated power of an antenna may not be equal to the total input power because of Ohmic power loss due to the finite conductivity (0) of the antenna, as well as loss due to the other factors. The radiation efficiency (er) is defined by: er -- P. Pr + Pe Pin where P, is the total radiated power and Pe is the power loss. Consider a Hertzian dipole made of a copper wire of radius a, length Al, and conductivity o. Calculate the power dissipated in the dipole (Pe= Pdiss) and the radiation efficiency er when a = 1mm and Al=10cm at the operating frequency f = 10Mhz