802 30min 50c Tsurr 25c Newton's cooling love say de a kl 12-T ) (. by integrating we get T(t) = Tot (Tour-Toekt (Tsina 50 80+ (25-80) e ( te in min -KX 30 2) 2 2) -KX30 -55 e 80 - 50 55 e KX30 30 KX 30 55 e 30 Now we have to find T (t) after te. I hour - KX 60 T(60) 2 Tot l Tsum - To) e 2 2 80 + (25-80) e-kx60 2 800 - 55 (e-kx 30 ) - 55 % (30) 55 x 30x30 55x55 4400-900 4400 900 250 2 280 55 2 80 280 900 55 2 85 3500 55 63.63 C (Ans)