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8:15 9 of 17 We can then use the acceleration to find the electron's speed. v = vo + at = 0 + (5.18

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8:15 9 of 17 We can then use the acceleration to find the electron's speed. v = vo + at = 0 + (5.18 10 m/s)(8.50 10 s) = 4.40 105 m/s Need Help? 5. [7/7 Points] Read It SerCP11 15.3.P.017.2/5 Submissions Used A small object of mass 3.86 g and charge -16.3 C is suspended motionless above the ground when immersed in a uniform electric field perpendicular to the ground. What are the magnitude and direction of the electric field? 2320 magnitude 2320 N/C downward direction downward Solution or Explanation In order to suspend the object in the electric field, the electric force exerted on the object by the field must be directed upward and have a magnitude equal to the weight of the object. Thus. Fe=qE=mg, and the magnitude of the electric field must be E = mg q = (3.86 g)(9.80 m/s) 16.3 106 C 1 kg 10 g = 2320 N/C. The electric force on a negatively charged object is in the direction opposite to that of the electric coursehero.com 8:29 DeVry PREVIOUS ANSWERS SERCP11 15.2.OP.001. 1/5 Submissions Used 2. [3.5/7 Points] DETAILS MY NOTES ASK YOUR TEACHER Two charged particles are a distance of 1.62 m from each other. One of the particles has a charge of 8.08 nC, and the other has a charge of 3.90 nC. (a) What is the magnitude (in N) of the electric force that one particle exerts on the other? 8.31e-8 X 1.08e-07 What law gives the magnitude of the force between two charged particles? What units should the charges be in to get a force in units of newtons? N (b) Is the force attractive or repulsive? attractive repulsive Solution or Explanation (a) From Coulomb's law, F = k , we have 12 F= (8.99 x 109 N. m/c) (8.08 x 10-9 C) (3.90 10-9 C) (1.62 m) (b) Since these are like charges (both positive), the force is repulsive. Need Help? Read It New Randomization = 1.08 x 10-7 N. 3. [-/6 Points] DETAILS SERCP11 15.2.P.007. 0/5 Submissions Used MY NOTES ASK YOUR TEACHER Two uncharged spheres are separated by 3.10 m. If 1.70 x 1012 electrons are removed from one sphere and placed on the other, determine the magnitude of the Coulomb force (in N) on one of the spheres, treating the spheres as point charges. HINT N Need Help? Read It Watch It Submit Answer 4. [-/6 Points] DETAILS SERCP11 15.3.OP.020. 0/5 Submissions Used MY NOTES ASK YOUR TEACHER Inside a radiation therapy device, an electron is in the presence of a uniform electric field with a magnitude of 270 N/C. (a) What is the magnitude of the acceleration of the electron (in m/s)? m/s (b) The electron is initially at rest. What is its speed (in m/s) after 9.50 x 10-9 s? m/s Need Help? Read It Submit Answer 5. [-/10 Points] DETAILS SERCP11 15.3.P.018. 0/5 Submissions Used MY NOTES ASK YOUR TEACHER (a) Determine the electric field strength at a point 1.00 cm to the left of the middle charge shown in the figure below. (Enter the magnitude of the electric field only.) 6.00 N/C 1.50 -2.00 3.00 cm 2.00 cm- webassign.net 8:29 A DeVry 5. [-/10 Points] DETAILS SERCP11 15.3.P.018. 0/5 Submissions Used MY NOTES ASK YOUR TEACHER (a) Determine the electric field strength at a point 1.00 cm to the left of the middle charge shown in the figure below. (Enter the magnitude of the electric field only.) 6.00 1.50 -2.00 C 3.00 cm 2.00 cm N/C (b) If a charge of -2.73 C is placed at this point, what are the magnitude and direction of the force on it? magnitude N direction ---Select--- Need Help? Read It Submit Answer 6. [-16 Points] DETAILS SERCP11 15.3.P.019. 0/5 Submissions Used MY NOTES ASK YOUR TEACHER An electric field of magnitude 5.25 x 105 N/C points due east at a certain location. Find the magnitude and direction of the force on a-5.20 C charge at this location. magnitude direction N ---Select--- Need Help? Read It Submit Answer 7. [-19 Points] DETAILS SERCP11 16.1.OP.006. 0/5 Submissions Used MY NOTES ASK YOUR TEACHER The figure below shows a charged particle, with a charge of q = +39.0 nC, that moves a distance of d = 0.168 m from point A to point B in the presence of a uniform electric field E of magnitude 250 N/C, pointing right. 9 A (a) What is the magnitude (in N) and direction of the electric force on the particle? N magnitude direction ---Select--- (b) What is the work (in J) done on the particle by the electric force as it moves from A to B? (c) What is the change of the electric potential energy (in J) as the particle moves from A to B? (The system consists of the particle and all its surroundings.) PEB PEA (d) What is the potential difference (in V) between A and B? VB-VA Need Help? Read It Submit Answer 8. [-16 Points] DETAILS V SERCP11 16.1.P.004. 0/5 Submissions Used MY NOTES ASK YOUR TEACHER Cathode ray tubes (CRTS) used in old-style televisions have been replaced by modern LCD and LED screens. Part of the CRT included a set of accelerating plates separated by a distance of about 1.34 cm. If the potential difference across the plates was 22.5 kV, find the magnitude of the electric field (in V/m) in the region between the plates. HINT V/m Need Help? Read It Watch It webassign.net 8. [-16 Points] DETAILS SERCP11 16.1.P.004. 0/5 Submissions Used MY NOTES ASK YOUR TEACHER Cathode ray tubes (CRTS) used in old-style televisions have been replaced by modern LCD and LED screens. Part of the CRT included a set of accelerating plates separated by a distance of about 1.34 cm. If the potential difference across the plates was 22.5 kV, find the magnitude of the electric field (in V/m) in the region between the plates. HINT V/m Need Help? Read It Watch It Submit Answer Home My Assignments Request Extension

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