%) 8.3.33-T EQuestion Help A traditional method of verifying mineralization grades in mining is to drill twinned holes, i.e., the drilling of a new hole, or "twin," next to an earlier drillhole. Geologists use data collected at both holes to estimate the total amount of a particular chemical compound present at the drilling site. The data in the associated table represent the chemicals percentages for a sample of 15 twinned holes drilled at a diamond mine. The geologists want to know if there is any evidence of a difference in the true chemical compound means of all original holes and their twin holes drilled at the mine. Complete parts a through e below Click the icon to view the mining data 5.4 10.9 5.9 8.3 9.9 5.8 7.8 10 5.5 6.8 0.1 0.2 2.7 0.6 0.9 1.2 2 10 8.5 8.5 10.7 5.4 9.8 4 5.6 9.3 7.2 0.5 12 10.5 6.9 11.2 13 0.2 9.7 15 7.4 Type integers or decimals. Do not round.) 9.2 c. Find the mean and standard deviation of the differences found in part b xd 0.146 Sd1.296 (Round to three decimal places as needed.) d. Use the summary statistics found in part b to find a 99% confidence interval for the true mean difference ("1st hole" minus "2nd hole") in chemical compound measurements CD (Round to two decimal places as needed.) Enter your answer in the edit fields and then click Check Answer. %) 8.3.33-T EQuestion Help A traditional method of verifying mineralization grades in mining is to drill twinned holes, i.e., the drilling of a new hole, or "twin," next to an earlier drillhole. Geologists use data collected at both holes to estimate the total amount of a particular chemical compound present at the drilling site. The data in the associated table represent the chemicals percentages for a sample of 15 twinned holes drilled at a diamond mine. The geologists want to know if there is any evidence of a difference in the true chemical compound means of all original holes and their twin holes drilled at the mine. Complete parts a through e below Click the icon to view the mining data 5.4 10.9 5.9 8.3 9.9 5.8 7.8 10 5.5 6.8 0.1 0.2 2.7 0.6 0.9 1.2 2 10 8.5 8.5 10.7 5.4 9.8 4 5.6 9.3 7.2 0.5 12 10.5 6.9 11.2 13 0.2 9.7 15 7.4 Type integers or decimals. Do not round.) 9.2 c. Find the mean and standard deviation of the differences found in part b xd 0.146 Sd1.296 (Round to three decimal places as needed.) d. Use the summary statistics found in part b to find a 99% confidence interval for the true mean difference ("1st hole" minus "2nd hole") in chemical compound measurements CD (Round to two decimal places as needed.) Enter your answer in the edit fields and then click Check
