8/9. An analysis of the design of a cap and bottle yielded the following: Bottle is 1" +/- 0.004" and the Cap is 1.008" +/- 0.003". Determine the following: Current Design Reject rate (RR) How would you re-specify the cap nominal with WC design How would you re-specify the cap nominal with 3 sigma design RR RR RR Given date: Bottle = 1 0.0014" = 1 0.0014" ; Cap= 1.008" 0.004" Solution: 1) Current design rate, R = 0.004 3 0.004 3 = 0.00133 0.00133 (0.00133) + (0.00133) 2 (0.00188 (AM) Total stake-up = 1+ 1,008 = 2.008" Man Stake-up = 1.004 + 1.012 = 2.016 Current average cap = 1.008-1= 0.008. 2 X-M 0-0.008 = 5-4-2553 0.00188 fe) = 0.0011/%= 0.000011 1 11 ppm (Am) We designs 1.008 Wc = 1.00k+ 0.004 $0.0000 = Cap = 1.004 : Bottle = 1.004 80 RR=0 (by design) Mij 30 design 1+30R = 1+3 (0.00188) 2=3 =1,0056 8(21= 0.00135 = 0.135% J = 135000 rpm Amowe 1) RR = 0.0011% = 11 PPM ii) wc design 1.008 with RR=0 i) 30 design = 1.00564 with RR= 135000 rpm