8-bit encoding going to 10-bit. (10 / 5) XXXXX XXXXX

ex) 0*FF 11111111 8-bit

encode

1011100100 10-bit

In a particular encoding scheme: a byte of information is encoded as 10-bits and then can be transmitted. The receiver can then decode the 10-bits to recover the original byte of information. Transmission is more reliable if the 10-bits do not have long runs of ones or zeros. For example, the information byte 0x00 is problematic to transmit because it is just a long run of zeros. So it can be encoded as the 10-bit number 0x174. This bit sequence doesn't have long runs and further is called balanced because it has the same number of ones and zeros. Based on this answer the following: a. How many 10-bit numbers are balanced? Show your work. b. What's the problem with trying to assign each possible 8-bit value a 10-bit balanced code? Briefly suggest a possible solution that encodes a byte as 10-bits