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9 . 2 1 . If 4 4 . 9 7 m l of a soln. of H C l are equivalent to 4 3

9.21. If 44.97ml of a soln. of HCl are equivalent to 43.76ml of a soln. of NaOH, and if 49.14ml of the latter will neutralize 0.2162g of KHC2O4*H2C2O4-2H2O, what vol. of water should be added to a liter of the HCl in order to make it 0.05000N? The answer should be 10.5mL
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