9. PLZ PLZ PLEAASE HELP!!

APPENDIX TABLE LINK : https://www.webassign.net/mendstat15/mendstat15_appendix_tables.pdf

For this assignment, you submit answers by question parts. The number of submissions remaining for each question part only changes if you submit or change the answer. Assignment Scoring Your last submission is used for your score. 1. [12 Points] MendStatlS 9.R.001. The pH factor is a measure of the acidity or alkalinity of water. A shing expert states that the best chance of catching bass occurs when the pH of the water is between 7.5 to 7.9. f Suppose you suspect that acid rain is lowering the pH of your favorite shing spot and you wish to determine whether the pH is less than 7.5. (a) State the alternative and null hypotheses that you would choose for a statistical test. r. Ho: [1 = 7.5 versus Ha: ,u i 7.5 (II. Ho: ,u 7.5 1" Ho: ,u i 7.5 versus Ha: ,u = 7.5 r. Ho: [.t = 7.5 versus Ha: ,u 7.5 0)) Does the alternative hypothesis in part (a) imply a one- or a two-tailed test? Explain. If\" . . . . . . Since it rs necessary to test that the average pH level rs less than 7.5, the test 1s two-tailed. t\" . . . . . . SHICB rt rs necessary to test that the average pH level rs different from 7.5, the test rs two- . F . . . . . tailed. Smce it is necessary to test that the average pH level 1s less than 7.5, the test IS one- . If" . . . . . tailed. Since it rs necessary to test that the average pH level is more than 7.5, the test is one- tailed. r Since it is necessary to test that the average pH level is different from 7.5, the test is one-tailed. (C) Suppose that a random sample of 50 water specimens gave pH readings with x = 7.2 and s = 0.3. Just glancing at the data, do you think that the difference x i 7.5 = 70.3 is large enough to indicate that the mean pH of the water samples is less than 7.5? (Do not conduct the test.) (d) Now conduct a statistical test of the hypotheses in part (a) and state your conclusions. Test using a = 0.05. Compare your statistically based decision with your intuitive decision in part (c). Find the test statistic and rejection region. (Round your answers to two decimal places. If the test is one-tailed, enter NONE for the unused region.) test statistic z = rejection region z > State your conclusion. C Fail to reject Ho. There is sufficient evidence to indicate that the mean pH of the water samples is less than 7.5. Reject Ho. There is insufficient evidence to indicate that the mean PH of the water samples is less than 7.5. Reject Ho. There is sufficient evidence to indicate that the mean pH of the water samples is less than 7.5. Fail to reject Ho. There is insufficient evidence to indicate that the mean pH of the water samples is less than 7.5. You may need to use the appropriate appendix table or technology to answer this question. 2. [-/2 Points] MendStat15 9.R.002. Is there a difference in the time spent doing household chores among men, depending on the generation to which they belong? The information that follows is adapted from an Advertising Age study, based on random samples of 1, 136 men and 795 women. Mean Standard Deviation n All Women 72 10.5 795 All Men 59 14.3 1,136 Millennials 72 9.1 345 Boomers 54 13.8 475 Xers 54 10.4 316 (a) Is there a significant difference in the average number of minutes spent doing household chores for men and women? Use a = 0.01. State the null and alternative hypotheses. (Use MM to represent men and use /w to represent women. )Ho: (Hw - MM) = 0 versus Ha: (Nw - MM) > O Ho: (Mw - MM) = 0 versus Ha: (Mw - MM) O Ho: (Mw - MM) = 0 versus Ha: (Mw - MM) # 0 Find the test statistic and rejection region. (Round your answers to two decimal places. If the test is one-tailed, enter NONE for the unused region.) test statistic z = rejection region z > State your conclusion. Ho is not rejected. There is sufficient evidence to indicate a difference in the average number of minutes spent doing household chores for men versus women. Ho is not rejected. There is insufficient evidence to indicate a difference in the average number of minutes spent doing household chores for men versus women. Ho is rejected. There is insufficient evidence to indicate a difference in the average number of minutes spent doing household chores for men versus women. Ho is rejected. There is sufficient evidence to indicate a difference in the average number of minutes spent doing household chores for men versus women. (b) Is there a significant difference in the average number of minutes spent doing household chores for millennial men and men classified as boomers? Use a = 0.01. State the null and alternative hypotheses. (Use /ML to represent millennial men and use MB to represent men classified as boomers.) C Ho: (MML - MB) = 0 versus Ha: (UML - MB) * 0 Ho: (UML -MB) 0 Ho: (UML - MB) # 0 versus Ha: (UML - MB) = 0 Ho: (UML -MB) = 0 versus Ha: (MML -MB) > 0 Ho: ( MML - MB ) = 0 versus Ha: (MML - MB) State your conclusion. Ho is rejected. There is insufficient evidence to indicate a difference in the average number of minutes spent doing household chores for Millennial men versus Boomers. Ho is rejected. There is sufficient evidence to indicate a difference in the average number of minutes spent doing household chores for Millennial men versus Boomers. Ho is not rejected. There is insufficient evidence to indicate a difference in the average number of minutes spent doing household chores for Millennial men versus Boomers. Ho is not rejected. There is sufficient evidence to indicate a difference in the average number of minutes spent doing household chores for Millennial men versus Boomers. (c) Is there a significant difference in the average number of minutes spent doing household chores for men classified as Xers and men classified as boomers? Usemilliliter. Cells treated with the lower concentration (0.6) of actinomycin D showed that 54 out of 70 developed normally, whereas only 22 out of 70 appeared to develop normally for the higher concentration (0.7). Do these data provide sufficient evidence to indicate a difference between the rates of normal RNA synthesis for cells exposed to the two different concentrations of actinomycin D? LA USE SALT (a) Find the p-value for the test. (Round your answer to four decimal places.) p-value = (b If you plan to conduct your test using a = 0.05, what will be your test conclusions? The p-value is less than alpha so Ho is rejected. There is insufficient evidence to indicate a difference between the rates of normal RNA synthesis for cells exposed to the two different concentrations of actinomycin D. The p-value is greater than alpha so Ho is not rejected. There is sufficient evidence to indicate a difference between the rates of normal RNA synthesis for cells exposed to the two different concentrations of actinomycin D. The p-value is less than alpha so Ho is rejected. There is sufficient evidence to indicate a difference between the rates of normal RNA synthesis for cells exposed to the two different concentrations of actinomycin D. The p-value is greater than alpha so Ho is not rejected. There is insufficient evidence to indicate a difference between the rates of normal RNA synthesis for cells exposed to the two different concentrations of actinomycin D. You may need to use the appropriate appendix table to answer this question. 5. [-/2 Points] MendStat15 9.R.007. How do California high school students compare to students nationwide in their college readiness, as measured by their SAT scores? The national average scores for the class of 2017 were 533 on Evidence-Based Reading and Writing and 527 on the math portion. / Suppose that 100 California students from the class of 2017 were randomly selected and their SAT scores were recorded in the following table. Evidence-Based Math Reading and Writing Sample Average 529 521 Sample Standard Deviation 98 95 (a) Do the data provide sufficient evidence to indicate that the average Evidence-Based Reading and Writing score for all California students in the class of 2017 differs from the national average? Use a = 0.05.State the null and alternative hypotheses. Ho: M = 533 versus Ha: M # 533 . Ho: M 527 Ho: Ml # 527 versus Ha: M = 527 " Ho: M = 533 versus Ha: M 533 Find the test statistic and the p-value. (Round your test statistic to two decimal places and your p- value to four decimal places.) Z = p-value = 1 State your conclusion. The p-value is less than alpha, so Ho is rejected. There is sufficient evidence to indicate that the average Evidence-Based Reading and Writing score for all California students in the class of 2017 is different from the national average. The p-value is less than alpha, so Ho is rejected. There is insufficient evidence to indicate that the average Evidence-Based Reading and Writing score for all California students in the class of 2017 is different from the national average. The p-value is greater than alpha, so Ho is not rejected. There is insufficient evidence to indicate that the average Evidence-Based Reading and Writing score for all California students in the class of 2017 is different from the national average. The p-value is greater than alpha, so Ho is not rejected. There is sufficient evidence to indicate that the average Evidence-Based Reading and Writing score for all California students in the class of 2017 is different from the national average. (b ) Do the data provide sufficient evidence to indicate that the average math score for all California students in the class of 2017 is different from the national average? Use a = 0.05. State the null and alternative hypotheses. Ho: u 527 Ho: [ # 527 versus Ha: M = 527 Ho: M = 533 versus Ha: M > 533 " Ho: M =527 versus Ha: u # 527 Ho: M = 533 versus Ha: M 0.5 Ho: p = 0.5 versus Ha: p # 0.5 Ho: p = 0.63 versus Ha: p # 0.63 Ho: p # 0.63 versus Ha: p = 0.63 " Ho: p 0.5 Find the test statistic and the p-value. (Round your test statistic to two decimal places and your p- value to four decimal places.) z= 1 p-value = State your conclusion. The p-value is greater than alpha, so Ho is not rejected. There is sufficient evidence to indicate that learning is taking place. The p-value is less than alpha, so Ho is rejected. There is sufficient evidence to indicate that learning is taking place. The p-value is greater than alpha, so Ho is not rejected. There is insufficient evidence to indicate that learning is taking place. The p-value is less than alpha, so Ho is rejected. There is insufficient evidence to indicate that learning is taking place. You may need to use the appropriate appendix table to answer this question. 7. [-/2 Points] MendStat15 9.R.011.S. If you choose to marry, what type of wedding site will you pick? A USA Today snapshot claims that 43% of all brides-to-be choose a house of worship for their wedding site.If the results of part (a) show that our claim was correct, construct a 99% confidence one-sided lower confidence bound for the average difference in heights between male and female college students. How much taller are males than females? (Round your answer to two decimal places. If our claim was incorrect, enter DNE.) Males are at least inches taller than females on average. You may need to use the appropriate appendix table or technology to answer this question. 9. [-/2 Points] MendStat15 9.R.013.S. The state of California monitors the progress of elementary-aged students whose native language is not English using the California English Language Development Test. The test results for two school districts for a certain school year follow. The proportion given is the proportion of 8th grade students judged as Advanced or Early-Advanced in English proficiency. District 1 2 Number Tested 350 450 Proportion 0.52 0.62 LA USE SALT Does the data provide sufficient evidence to indicate that there is a difference in the proportion of students in the two districts who are Advanced or Early-Advanced in English proficiency? Use a = 0.01. State the null and alternative hypotheses. (Use pi for District 1 and p2 for District 2.) Ho: (p1 - p2) = 0 versus Ha: (p1 - pz) 0 Ho: (P1 - p2) = 0 versus Ha: (P1 - pz) > 0 Ho: (p1 - p2) # 0 versus Ha: (p1 - p2) = 0 C Ho: (p1 - p2) = 0 versus Ha: (pi - p2) # 0 Find the test statistic and rejection region. (Round your answers to two decimal places. If the test is one-tailed, enter NONE for the unused region. test statistic z = rejection region z > State your conclusion. Ho is rejected. There is insufficient evidence to indicate that the proportion of students who are Advanced or Early-Advanced in English proficiency differs for these two districts. Ho isnot rejected. There is sufficient evidence to indicate that the proportion of students who are Advanced or Early-Advanced in English proficiency differs for these two districts. Ho is rejected. There is sufficient evidence to indicate that the proportion of students who are Advanced or Early-Advanced in English proficiency differs for these two districts. Ho is not rejected. There is insufficient evidence to indicate that the proportion of students who are Advanced or Early-Advanced in English proficiency differs for these two districts. You may need to use the appropriate appendix table to answer this question. 10. [-/2 Points] MendStat15 9.R.015. How much training time does it take to become a world-class breaststroke swimmer? A survey reported the number of meters per week swum by two groups of swimmers-those who competed only in breaststroke and those who competed in the individual medley (which includes breaststroke). The number of meters per week practicing the breaststroke swim was recorded and the summary statistics are shown here Breaststroke Individual Medley Sample Size 130 80 Sample Mean 9,016 5,853 Sample Standard Deviation 7,162 1,960 (a) Construct a 99% confidence interval for the difference in the average number of meters that breaststroke versus individual medley swimmers swam. (Use Mi for the breaststroke and M2 for the individual medley and compare (M1 - M2). Round your answers to the nearest whole number.) meters to meters (b) How much longer do pure breaststroke swimmers practice that stroke than individual medley swimmers? (Round your answers to the nearest whole number.) Pure breaststroke swimmers swim, on average, between and more meters per week than individual medley swimmers. What is the practical reason for this difference? Pure breaststroke swimmers know how difficult their stroke is and practice. Swimmers in the individual medley have other strokes to practice. Pure breaststroke swimmers are more likely to practice than other swimmers. Swimmers in the individual medley have teammates so they don't need to practice as much. You may need to use the appropriate appendix table or technology to answer this