9-58.An article in the ASCE Journal of Energy Engineering (1999, Vol. 125, pp. 59-75) describes a study of the thermal inertia properties of autoclaved aerated concrete used as a building material. Five samples of the material were tested in a structure, and the average interior temperatures (C) reported were as follows: 23.01, 22.22, 22.04, 22.62, and 22.59.

(a) Test the hypotheses H₀: = 22.5 versus H₁: 22.5, using 0.05. Find the P-value.

(b) Is the data normally distributed?

(c) If you set = 0.05, what are your conclusions for the analysis?

	a.	The p-value is greater than , so we reject the null hypothesis and conclude that the mean is less than 23.
	b.	The p-value is less than , so we fail to reject the null hypothesis and conclude that there is no evidence that the mean is less than 23.
	c.	The p-value is less than , so we fail to reject the null hypothesis and conclude that the mean is less than 23.
	d.	The p-value is less than , so we reject the null hypothesis and conclude that the mean is less than 23.

(d) what would be the relationship between a confidence interval and the conclusions from a hypothesis test (assume the same value of is used for both)?

	a.	Since you've rejected the null hypothesis, 23 will not be in the confidence interval or bound
	b.	Since you've failed to reject the null hypothesis, 23 will not be in the confidence interval or bound
	c.	Since you've rejected the null hypothesis, 23 will be in the confidence interval or bound
	d.	Since you've failed to reject the null hypothesis, 23 will be in the confidence interval or bound