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97. To determine the value of the definite integral: x-3 dx x? - 6x + 10 a. Complete the square of the denominator of the

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97. To determine the value of the definite integral: x-3 dx x? - 6x + 10 a. Complete the square of the denominator of the integrand: x? - 6x + 10 = + b. Determine the anti-derivative using an appropriate substitution: X-3 x2 - 6x + 10 dx = c. Use the anti-derivative to evaluate the definite integral: X-3 X2 - 6x + 10 dx

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