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A 0.025-kg bullet enters a 2.35-kg watermelon with a speed of 217 m/s and exits the opposite side with a speed of 109 m/s.
A 0.025-kg bullet enters a 2.35-kg watermelon with a speed of 217 m/s and exits the opposite side with a speed of 109 m/s. If the melon was originally at rest, then what speed will it have as the bullet leaves its opposite side?
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To solve this problem we can apply the principle of conservation of momentum ...
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College Physics
Authors: Jerry D. Wilson, Anthony J. Buffa, Bo Lou
7th edition
9780321571113, 321601831, 978-0321601834
