Question
A 0.4 kg cart is attached between two horizontal springs, of stiffness 4 N/m, which are attached at each end of a track. The
A 0.4 kg cart is attached between two horizontal springs, of stiffness 4 N/m, which are attached at each end of a track. The cart has low-friction wheels, so friction is negligible. The relaxed length of each spring is 0.1 m. I x=0 x=0.5 m x=1.0 m If you release the cart from rest (when it is displaced to the left of equilibrium as shown above), what will be its position 0.1 s later? (Use the approximation avg future /m.) 7(1 (1= 0.1 s) = (i 0.32 Save for Later Using multiple attempts will impact your score. 40% score reduction after attempt 3 Your answer is partially correct. Now, at 10.1s, what is the net force by the springs on the cart? Fnet (1 = 0.1 s) = (i -0.032 ) m 0 > N
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Physics
Authors: Alan Giambattista, Betty Richardson, Robert Richardson
2nd edition
77339681, 978-0077339685
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