A 1-1/2 nominal schedule 40 stainless steel pipe, dimensions given below, carries steam at a temperature such that it maintains an outside surface temperature of T2 = 250 F on the pipe. The pipe is exposed to air at To = 70 F. The convection heat transfer coefficient in the air is 1.5 Btu/(hr.ft.R). For a unit length of the pipe, L = 1 ft: (OD = 1.9 in = 0.1583 ft = 2 R2, ID = 0.1342 ft = 2R1) a) Calculate the heat loss when there is no insulation. b) It is desired to reduce the heat loss in part (a) by adding an insulation material with a thermal conductivity, K, value of 0.14 Btu/(hr.ft.R) to the pipe. Develop a computer programming code so to calculate the heat loss as a function of the insulation thickness, t and R3 so to show a range of heat loss reductions up to 50%. Include the following in your calculations: 1) What is the critical radius of insulation? 2) Create a table with four columns: t, R3, Q/L, % heat reduction, and T3. Plot Q/L vs t, Q/L vs R3, and % heat reduction vs t. Make a short comment by what you observe. ) risulation R /R3 R1 (6) R 23 223= ln (R3/22), L='ht Tesort wit wrong ( K= insulation = 0.14 Blu Cholt.R) A=20R3) 2TKL 300 HA A 1-1/2 nominal schedule 40 stainless steel pipe, dimensions given below, carries steam at a temperature such that it maintains an outside surface temperature of T2 = 250 F on the pipe. The pipe is exposed to air at To = 70 F. The convection heat transfer coefficient in the air is 1.5 Btu/(hr.ft.R). For a unit length of the pipe, L = 1 ft: (OD = 1.9 in = 0.1583 ft = 2 R2, ID = 0.1342 ft = 2R1) a) Calculate the heat loss when there is no insulation. b) It is desired to reduce the heat loss in part (a) by adding an insulation material with a thermal conductivity, K, value of 0.14 Btu/(hr.ft.R) to the pipe. Develop a computer programming code so to calculate the heat loss as a function of the insulation thickness, t and R3 so to show a range of heat loss reductions up to 50%. Include the following in your calculations: 1) What is the critical radius of insulation? 2) Create a table with four columns: t, R3, Q/L, % heat reduction, and T3. Plot Q/L vs t, Q/L vs R3, and % heat reduction vs t. Make a short comment by what you observe. ) risulation R /R3 R1 (6) R 23 223= ln (R3/22), L='ht Tesort wit wrong ( K= insulation = 0.14 Blu Cholt.R) A=20R3) 2TKL 300 HA