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A 185.0 mL solution of 2.714 M strontium nitrate is mixed with 215.0 mL of a 3.460 M sodium fluoride solution. Calculate the mass of

A 185.0 mL solution of 2.714 M strontium nitrate is mixed with 215.0 mL of a 3.460 M sodium fluoride solution. Calculate the mass of the resulting strontium fluoride precipitate.

mass:

g

Assuming complete precipitation, calculate the final concentration of each ion. If the ion is no longer in solution, enter a 0 for the concentration.

[Na+]=

M

[NO−3]=

M

[Sr2+]=

M

[F−]=

M

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I Waite a balanced chenical equation Sr NO2 2NAF Sa Fg 2 NANO3 ... blur-text-image

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