a$)$ A rate constant increases with the increase of pressure. As the pressure increases, the number of reactant particles per unit volume will also increase. The collision rate is higher and therefore the rate of reaction will increase. Besides rate constant, fluid power also increases with the pressure.

A rate constant depends on temperature according to the formula:

$k=2$exp$[\frac{-E}{8\mathrm{.}314(T)}]$

Where $k=$ rate constant $(\frac{L}{m}ol*min)$

$T=$ reactor temperature $(K)$

$E=$ reaction activation energy $(\frac{J}{m}ol)$

i$.$ Identify the unit for constant values of $2$ and $8\mathrm{.}314.$

ii$.$ Determine the rate constant in $\frac{L}{m}ol*min$ when the reactor temperature is $50F$ and activation energy is $1000ca\frac{l}{l}$ m $*mol.$

iii. Determine the new constant values if all variables are stated in CGS unit.

iv$.$ Convert $25$ calories $($cal$)$ of power into $lbm*\frac{m^2}{m}i{n}^2$ and horsepower second $($hp$.$s$).$

$($Given: $T(F)=1\mathrm{.}8T(C)+32)$