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A bag contains 24 coloured counters, three blue, four red, nine green and eight yellow. If five counters are chosen at random from the bag,

A bag contains 24 coloured counters, three blue, four red, nine green and eight yellow. If five counters are chosen at random from the bag, what is the probability of selecting exactly 3 green and no blue counters?

Use the equation:

P(x)= (aCx)*(n-aCr-x)*(a(blue)Cx(blue))(nCr)

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