A ball falls from height of 18.5 m, hits the floor, and rebounds vertically upward to height of 15.5 m. Assume that mba\" = 0.290 kg. (a) What is the impulse {in kg - mfs) delivered to the ball by the oor? magnitude \\:| kg i sz direction (b) If the ball is in contact with the floor for 0.0300 seconds, what is the average force (in N) the floor exerts on the ball? magnitude \\:| N direction Initial velocity = 12 ghi 2 x 9 . 81 x 18.5 U = 19. 04 20m0 /s . Velocity Final = 12 ght 2 x 3 . 81 X 15.5 V - 17 .42 98mm / s . upward is positivedion. U - - 19. 0420 707 / s ,V= 17. 4298 m/s. Impules J = MAV = 0. 29 ( 17 . 4298 - (- 19.092 ) J = 10 . 5 7 6 8 mm / s Force - lompulse 10.5768 - 352.56 N time '03 F = 352. 56 1