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A ball is launched vertically upward with an initial velocity of 100 feet per second. The distance s (in feet) of the ball from the

A ball is launched vertically upward with an initial velocity of 100 feet per second. The distance s (in feet) of the ball from the ground after t seconds is s(t)=100t-16t2. When is the ball 50 feet above the ground? Give an exact answer

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