A ball is tossed upward from a tall building, and its upward in of the time t, in seconds, since the ball was thrown. The formula is V = 40 - 32t if we ignore air resistance. The function V is positiv s rising and negative when the ball is falling. (a) Express using functional notation the velocity 1 second after the ball is thrown, and then calculate that value. = 16 ft per sec s the ball rising or falling then? O Because the upward velocity is positive, the ball is rising. O Because the upward velocity is positive, the ball is falling. O Because the upward velocity is negative, the ball is rising O Because the upward velocity is negative, the ball is falling. b) Find the velocity 2 seconds after the ball is thrown. it per sec s the ball rising or falling then? O Because the upward velocity is positive, the ball is rising. O Because the upward velocity is positive, the ball is falling. O Because the upward velocity is negative, the ball is rising. O Because the upward velocity is negative, the ball is falling. The velocity is 0 ; the ball is falling off the building O The velocity is 0; the ball is resting on the ground O The velocity is 0; the ball is at the peak of its flight O The velocity is 0; the ball is resting on the building. (d) By how much does the velocity change from 1 to 2 seconds after the ball is thrown? ft per sec By how much does the velocity change from 2 to 3 seconds after the ball is thrown? ft per sec By how much does the velocity change from 3 to 4 seconds after the ball is thrown? ft per sec Compare the answers to the last three qu s and explain in practical terms. This means that position of the ball changes by 32 feet for each second that passes. O This means that the velocity increases by 32 feet per second for each second that passes. O This means that the or each second that passes. This indicates that the velocity of the ball is constant at 32 feet per second per second. 2 The following is the graph of a function f = f(x). Where does the graph reach a maximum, and what is that maximum value? A(x ) =