A ball rolls off the edge of a table. Let the time the ball leaves the table surface be t = 0. If the table is horizontal, its velocity as a function of time is given by 3 = 1.50i 9.80tj, with G in m/s and tin s. The ball's displacement from the edge of the table from t = 0 to t = 0.465 s (while it is in flight), is given by - 0.465% Ar = j v dt. 0 Use this theorem to perform the integration: /[P+ woo] dx = P/dx+ Q/f(x)dx. Consider the units and unit vectors to be the constants P and Q. Integrate to determine the ball's displacement (in m) from the table edge at 0.465 5. (Express your answer in vector form. Do not include units in your answer.) A; = 1.6527 x Substitute the vector expression into the integral, and apply the theorem to separate the vector components into two integrals, which you can solve individually. Be sure to keep track of your signs. m