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A basketball player is running at 4.90 m/s directly toward the basket when he jumps into the air to dunk the ball. He maintains his
A basketball player is running at 4.90 m/s directly toward the basket when he jumps into the air to dunk the ball. He maintains his horizontal velocity. (For each answer, enter a number.) (a) What vertical velocity (in m/s) does he need to rise 0.750 meters above the floor? m/s (b) How far (in m) from the basket (measured in the horizontal direction) must he start his jump to reach his maximum height at the same time as he reaches the basket? m /2.85 Points] DETAILS OSCOLPHYS2016 3.4.P.042. MY NOTES AS Suppose a soccer player kicks the ball from a distance 30 m toward the goal. Find the initial speed of the ball if it just passes over the goal, 2.4 m above the ground, given the initial direction to be 400 above the horizontal. m/s Additional Materials Reading /2.85 Points] DETAILS OSCOLPHYS2016ACC 4.3.WA.009. MY NOTES ASK YOUR TEACHER PRA An object of mass 0.53 kg is initially at rest. When a force acts on it for 2.9 ms it acquires a speed of 13.4 m/s. Find the magnitude (in N) of the average force acting on the object during the 2.9 ms time interval. (Enter a number.)It R Running speed of the basketball player = 4 = 4.90 m/ s ( to wards the basket ) a ) Let v = vertical velocity needed he = rise above floor = 0. 750 mR- 2 a= acceleration of the player in vertical direction. =g using kinematic equation V2 = yzfzas, in the vertical direction So, v2 - 2gh Vz 2gh V = 2gh V = / 2x9. 81 X0. 750 V = 10.405 m/s.P . 3 Therefore , the vertical velocity needed to rise 0. 750 m above the floor= jo. 405m/s. b ) Let R = distance of player to from reach maximum height using the Kinematic epcation, V = U+ at 0 = 10. 405 - 9 x7 7 = 10.405 9. Q1 = 1. 060ser.8 -4 The time taken by the player to reach basket = 1 = 1.060sec . So, Running Speed of basketball playes = Distance covered Time, R R = UX R = 4. 90 X 1 . 060 R = 5. 194 m Ans3 - mass, m = 0.52kg final velocity = 13.4 m/s Time , t = 2.9x 10 3 sec. solution - The change in momentum = impulse that it experiences Ft = (m AV ) F = m ( vs - vi) Substituting the Known values we get,
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