A basketball player jumps straight up for a ball. To do this, he lowers his body 0.290 m and then accelerates through this distance by forcefully straightening his legs. This player leaves the floor with a vertical velocity sufficient to carry him 0.940 m above the floor.

(a)Calculate his velocity (in m/s) when he leaves the floor. m/s

(b)Calculate his acceleration (in m/s²) while he is straightening his legs. He goes from zero to the velocity found in part (a) in a distance of 0.290 m. m/s²

(c)Calculate the force (in N) he exerts on the floor to do this, given that his mass is 104 kg.