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A basketball player jumps straight up for a ball. To do this, he lowers his body 0.315 m and then accelerates through this distance

     

A basketball player jumps straight up for a ball. To do this, he lowers his body 0.315 m and then accelerates through this distance by forcefully straightening his legs. This player leaves the floor with a vertical velocity sufficient to carry him 0.895 m above the floor. For this problem, use a coordinate system where up is positive. Part (a) Calculate his velocity when he leaves the floor in m/s. Part (b) Calculate his acceleration, in m/s, while he is straightening his legs. He goes from zero to the velocity found in part (a) in a distance of 0.315 m. Part (c) Calculate the magnitude of the force he exerts on the floor to do this, in newtons, given that his mass is 114 kg.

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