A basketball star covers 2.55 m horizontally in a jump to dunk the ball. His motion through space can be modeled precisely as that of a particle at his center of mass. His center of mass is at elevation 1.02 m when he leaves the floor. It reaches a maximum height of 1.95 m above the floor and is at elevation 0.890 m when he touches down again. (a) Determine his time of flight (his "hang time"). 0.901 VS (b) Determine his horizontal velocity at the instant of takeoff. 2.83 m/s (c) Determine his vertical velocity at the instant of takeoff. X The correct answer is not zero. m/s (d) Determine his takeoff angle. o above the horizontal (e) For comparison, determine the hang time of a whitetail deer making a jump with center-of-mass elevations y; = 1.20 m, ymax = 2.25 m, and y, = 0.780 m. S Need Help? Read It