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A batch reactor is charged with 11.10kmol of sulfur dioxide and 5.80kmol oxygen, which react reversibly to form sulfur trioxide. The equilibrium constant for this

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A batch reactor is charged with 11.10kmol of sulfur dioxide and 5.80kmol oxygen, which react reversibly to form sulfur trioxide. The equilibrium constant for this reaction at the pressure and emperature of the reactor is provided below. SO2+1/2O2SO3K=ySO2(yO2)1/2ySO3=11.5 - Check stoichiometry and expressions for number of moles. What is the maximum percent conversion of the limiting reactant (i.e. the percent conversion at equilibrium)? % Calculate the mole fraction of each species at equilibrium. ySO2= Increasing the Excess Reactant What is the maximum percent conversion of sulfur dioxide that can be attained by increasing the amount of oxygen fed to the reactor? % Required Excess for a Set Conversion What amount of oxygen should be fed to the reactor to achieve 85.7% conversion of 11.10kmol of sulfur dioxide? kmol2

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