Answered step by step
Verified Expert Solution
Question
1 Approved Answer
A block with mass m =6.8 kg is hung from a vertical spring. When the mass hangs in equilibrium, the spring stretches x = 0.22
A block with mass m =6.8 kg is hung from a vertical spring. When the mass hangs in equilibrium, the spring stretches x = 0.22 m. While at this equilibrium position, the mass is then given an initial push downward at v = 5 m/s. The block oscillates on the spring without friction.
- 1) What is the spring constant of the spring?
- 2 )What is the oscillation frequency?
- 3) After t = 0.3 s what is the speed of the block?
- 4) What is the magnitude of the maximum acceleration of the block?
- 5) At t = 0.3 s what is the magnitude of the net force on the block?
- 6) Where is the potential energy of the system the greatest?
Step by Step Solution
There are 3 Steps involved in it
Step: 1
Lets solve these step by step 1 Spring Constant k Hookes Law states F kx where F is the force exerted by the spring k is the spring constant and x is ...Get Instant Access to Expert-Tailored Solutions
See step-by-step solutions with expert insights and AI powered tools for academic success
Step: 2
Step: 3
Ace Your Homework with AI
Get the answers you need in no time with our AI-driven, step-by-step assistance
Get Started