A box of mass M : 24.9kg is on a rough slope. The coefficient of static friction between the box and the slope is ,u = 0.2. The slope makes an angle of 6 = 23.75\" with the horizontal. The box is subject to a force of magnitude T = 104.31N which is directed up the slope parallel to the slope. The acceleration due to gravity is 9.8m/52. (The input below will accept answers with no more than 1% variation from the correct value.) What is the magnitude of the normal force the box experiences? N A box of mass M = 24.9kg is on a rough slope. The coefficient of static friction between the box and the slope is ,u : 0.2. The slope makes an angle of 6 = 23.75D with the horizontal. The box is subject to a force of magnitude T = 104.31N which is directed up the slope parallel to the slope. The acceleration due to gravity is 9.8111/52. (The input below will accept answers with no more than 1% variation from the correct value.) What is the magnitude of the friction force the box experiences? N A box of mass M : 24.9kg is on a rough slope. The coefficient of static friction between the box and the slope is p. : 0.2. The slope makes an angle of 6' = 23.75D with the horizontal. The box is subject to a force of magnitude T = 104.31N which is directed up the slope parallel to the slope. The acceleration due to gravity is 9.8m/52. (The input below will accept answers with no more than 1% variation from the correct value.) What range of values for T is consistent with static equilibrium? You must get both the upper and lower limits correct to get credit for this question. Nng N