A car moves along a horizontal road with constant velocity = (47.6 m/s) i until it encounters a smooth inclined hill. It climbs the hill with constant velocity i + v,y j = (38.2 m/s)i + (4.48 m/s) j Vo = V0,x V davg = V1,x as indicated in the figure. The period of time during which the car changes its velocity is At = 1.24 s. 270. 50% Part (a) Enter an expression, in Cartesian unit-vector notation, for the average acceleration of the car during the given time period using the provided. davg=(V1x Vox) At+ (vy) /At Correct! 50% Part (b) What is the magnitude, in meters per squared second, of the car's average acceleration during the given time period. m/s Grade Deduc Potent