A certain herbal remedy being tested may be effective in increasing the life expectancy in people who have a rare disease. A control group consists of 25 subjects who have not taken the remedy and have a mean life expectancy of 72.1 years. A treatment group of the same size that has been given the remedy has a mean life expectancy of 79.5 years. After rerandomizing through simulation, the distribution plot for the differences of means was created and is shown below. E'emiveness of Herbal Remedy Dicrcncc oEMcans . X H XL . . . . . . Hint: SD = T,where SD Is the standard devratlon, XH Is the high value, and XL Is the low value SD Hint: M E = i2 - , where SD is the standard deviation and N is the sample size W Using N = 50, what is the margin of error (ME), rounded to the nearest hundredth, and is the naturopathic remedy effective in increasing the life expectancy of people with this rare disease? 0 ME = 1:267 and yes, the remedy is effective in increasing the life expectancy in people because the original difference of means of 7.4 years is beyond, statistically, what we would expect if the differences were random 0 ME = 2.03 and yes, the remedy is effective in increasing the life expectancy in people because the original difference of means of 7.4 years is beyond, statistically, what we would expect if the differences were random 0 ME = 1:841 and no, the remedy is not effective in increasing the life expectancy in people because the original difference of means of 7.4 years is within, statistically, what we would expect if the differences were random 0 ME = 1:574 and no, the remedy is not effective in increasing the life expectancy in people because the original difference of means of 7.4 years is within, statistically, what we would expect if the differences were random