Question
A cheetah is crouched 20m to the east of an observer (Fig. 2.6a). At time t=0 the cheetah begins to run due east toward an
A cheetah is crouched
20m
to the east of an observer (Fig. 2.6a). At time
t=0
the cheetah begins to run due east toward an antelope that is
50m
to the east of the observer. During the first
2.0s
of the attack, the cheetah's coordinate
x
varies with time according to the equation
x=20m+(5.0(m)/(s^(2)))t^(2)
. (a) Find the cheetah's displacement between
t_(1)=1.0s
and
t_(2)=2.0s
. (b) Find its average velocity during that interval. (c) Find its instantaneous velocity at
t_(1)=1.0s
by taking
\\\\Delta t=0.1s
, then
0.01s
, then
0.001s
. (d) Derive an expression for the cheetah's instantaneous velocity as a function of time, and use it to find
v_(x)
at
t=1.0s
and
t=2.0s
.
Step by Step Solution
There are 3 Steps involved in it
Step: 1
Get Instant Access to Expert-Tailored Solutions
See step-by-step solutions with expert insights and AI powered tools for academic success
Step: 2
Step: 3
Ace Your Homework with AI
Get the answers you need in no time with our AI-driven, step-by-step assistance
Get Started