A chemical compound decays over time when exposed to air, at a rate proportional to its concentration to the power of 3/2. The differential equation for its instantaneous concentration is given as () = 0.1 3 2 + 10(1 3 ) where n(t) is the concentration at time t and the initial concentration at t=0 is n0 =2000. Solve the equation to find the concentration from t=0 to t=0.5 using step size of 0.125 with a) explicit