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A client host sends a W = 8 0 0 - byte file to a server which is L = 1 2 0 0 km

A client host sends a W =800-byte file to a server which is L =1200 km away over a
B =2.5 Gb/s optical fibre network.
(i) Calculate the upper bound of the link efficiency (
LEUB
) for this transmission
assuming that the speed of light in optical fibre is c =200,000 km/s.
(ii) What would be the
LEUB
for a link with transmission speed B =2.5 Mb/s?
Explain why the results for the calculated values of
LEUB
in parts (i) and (ii) are
different.
(iii) Calculate the necessary size of the file W which will allow to achieve a 50%
LEUB
for a link you considered in part (i)

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